Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
You can return the answer in any order.
Example:
Input: nums = [2,7,11,15], target = 9 Output: [0,1] Explanation: Because nums[0] + nums[1] == 9, we return [0, 1].
The brute-force approach would be to use two nested loops to check every pair of numbers, which would be O(n²). We can do much better using a hash table (or a JavaScript Map).
nums.num, calculate the required complement: complement = target - num.complement exists in our hash map.
num and its index to the hash map.This approach has a time complexity of O(n) because we iterate through the array once, and each hash map lookup is O(1) on average. The space complexity is O(n) to store the hash map.
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